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Another  Way  to  find  NcR  using  higher  Secondary school  formula :P


void pre()
{
    for(int i=0;i<=4000;i++)
        nCr[i][0] = 1 ;
    for(int i=1;i<=4000;i++)
        for(int j=1;j<=i;j++)
            nCr[i][j] = ( nCr[i-1][j-1] + nCr[i-1][j] ) % MOD ;
}

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