Just programming

Given a set of non-negative integers, and a value sum , determine if there is a subset of the given set with sum equal to given sum . https://www.geeksforgeeks.org/subset-sum-problem-dp-25/             Recursion                                            class Solution {          static boolean isSumK(int[] nums, int curin, int curSum) {                  if(curSum==0) {             return true;         }                  if(curin<0) {             return false;     ...

 https://www.geeksforgeeks.org/subset-sum-problem-dp-25/ class Solution {          static boolean isSumK(int[] nums, int curin, int curSum) {                  if(curSum==0) {             return true;         }                  if(curin<0) {             return false;         }                  return isSumK(nums, curin-1, curSum-nums[curin])              || isSumK(nums, curin-1, curSum);     }     static Boolean isSubsetSum(int N, int arr[], int sum) {         // code here         return isSumK(arr, N-1, sum);     } }

Group Anagrams https://leetcode.com/problems/group-anagrams/  class Solution {     public List<List<String>> groupAnagrams(String[] strs) {                  HashMap<String, List<String>> hm = new HashMap<>();                  for(int i=0;i<strs.length;i++) {             char[] s = strs[i].toCharArray();             Arrays.sort(s);             String k = new String(s);             if(hm.containsKey(k)) {                 hm.get(k).add(strs[i]);             } else {                 List<String> ls = new ArrayList<String>();                 ls.add(strs[i]);     ...

Linked List in Java without Collections class Node { int data ; Node next ; Node ( int data) { this . data = data ; this . next = null; } } public class Main { public static void main (String[] args) { Node n1 = new Node( 5 ) ; Node n2 = new Node( 6 ) ; Node n3 = new Node( 7 ) ; Node n4 = new Node( 8 ) ; n1. next = n2 ; n2. next = n3 ; n3. next = n4 ; Node start = n1 ; while (start!= null ) { System. out .println(start. data + " " ) ; start = start. next ; } } }